Question

If the ratio of fundamental units in two systems is 1:3 then the ratio of momentum in the two system is
1) 1:3
2) 1:9
3) 1:27
4) 3:1

Answer 1

Answer:

1) 1:3

Explanation:

All units in system one :  those in system two = 1 : 3 (Given)

Units in system one are  1/3 of those in system 2

Angular momentum  =  mass  × angular velocity =  m  × ω

=  mass ×  linear velocity / radius  

=   mass × radians / sec

Thus, momentum 1  =  (1/3)  × (1/3)  /  (2/3)  of system two

AM1 : AM2  =  1/3  or 1:3    

Therefore, the ratio will remain the same.

Hence, If the ratio of fundamental units in two systems is 1:3 then the ratio of momentum in the two system is 1:3.

Answer 2

Answer:

Explanation:

All units in system one : those in system two = 1 : 3 (Given)

Units in system one are 1/3 of those in system 2

Angular momentum = mass × angular velocity = m × ω

= mass × linear velocity / radius

= mass × radians / sec

Thus, momentum 1 = (1/3) × (1/3) / (2/3) of system two

AM1 : AM2 = 1/3 or 1:3

Therefore, the ratio will remain the same.

Hence, If the ratio of fundamental units in two systems is 1:3 then the ratio of momentum in the two system is 1:3.