Question

If the ratio of gold and copper in a jewelry is 9:11 if pure gold weighs 540g what is the weight of copper​

Answer 1

Answer:

since ratio of elements are given as 9:11 so amount of copper present in 540 g is

Step-by-step explanation:

11/9*540 and this gives us 297 g

thanks comment if you don't understand it

Answer 2

Answer :

• The weight of copper is 297 g.

Step-by-step explanation:

Given :

• The ratio of gold to copper in the ornament is 9 : 11.

So,

Gold : Copper = 9 : 11

• The total weight of ornament = 540 g

To find :

• The weight of copper =?

Let,the variable = x (Here x is assumed as a variable to calculate the weight of the gold and copper present in that piece of ornament)

So, the weight of gold and copper by multiplying the variable to respective ratio elements are -

Gold = 9 x

Copper = 11 x

Now,to form an equation,we will take the total weight of the ornament as the RHS of the equation.

So,the equation will be -

9x + 11x = 540

20x = 540

x = 540/20

x = 27

The value of the variable is 297.

Now,

Copper amount in the ornament = (value of the variable × value of the respective ratio term )= (27 × 11) = 297 g

There is 297 g of copper in that piece of ornament. (Answer)