Question

If the ratio of length and breadth of rectangle 7:2 and its perimeter is 810cm. find area of rectangle.​

Answer 1

Answer:

28350cm^2

Step-by-step explanation:

let length of rectangle be 7x and breadth be 2x,

we know that perimeter of rectangle= 2(l+b)

then A.T.Q,

2(7x+2x)= 810

14x+4x=810

18x=810

x=810/18= 45

length= 7x= 7×45= 315cm

breadth= 2x=2×45= 90cm

Also ,

Area of rectangle= l×b

so, by putting values,

Area of rectangle= 315cm×90cm

Area of rectangle= 28350cm^2

Answer 2

Answer:

★ Given

• ✒ Ratio of length and breadth of rectangle = 7:2
• ✒ Perimeter of Rectangle = 810cm

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★ To Find

• ✒ Area of Rectangle

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★ Using Formula

• ✒ Area of Rectangle = Lenght × Breadth

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★ Solution

Let the sides of Rectangle be 'x'

So,

• ↝ Length = 7×x = 7x
• ↝ Breadth = 2×x = 2x

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➬ Firstly we Find the sides of Rectangle,

So,

$\red \leadsto\sf \pink{2(Lenght + Breath)}= \purple{ Perimeter }$

$\red \leadsto \sf \pink{2(7x + 2x) }= \purple {810 \: cm}$

$\red \leadsto \sf \pink{2 \times 9x} = \purple {810}$

$\red \leadsto\sf \pink{18x} = \purple{ 810}$

$\red \leadsto \sf \pink{x} = {\purple{\cancel \dfrac{810}{18}}}$

$\red\leadsto \sf \pink{x} = \purple {45}$

$\large{\underline {\boxed {\sf{ \pink{x}= \purple{45}}}}}$

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Sides :-

• ↝ Length = 7×45 = 315 cm
• ↝ Breadth = 2×45 = 90 cm

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➬ Now We Find the Area of Rectangle

So,

${\red\longmapsto\textsf{\purple{Area of Rectangle} = \pink{Length x Breadth}}}$

$\red \longmapsto \sf \purple{Area} = \pink{315 \times 90}$

$\red \longmapsto\sf \purple{Area }= \pink{28350 \: {cm}^{2} }$

$\Large{\underline {\boxed {\sf{ \purple{Area}= \pink{28350 \: {cm}^{2}}}}}}$

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★ Therefore

✒ The Area of Rectangle is 28350 cm²