Question

If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a, b, and c, respectively. The ratio between the increase in lengths of brass and steel wires would be(a) $\frac{b^{2}a}{2c}$(b) $\frac{bc}{2a^{2}}$(c) $\frac{ba^{2}}{2c}$(d) $\frac{a}{2b^{2}c}$

Answer 1

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Next similar questionQ)

If the ratio of lengths , radii and Young's modulli of two wires in the figure shown are 2,4, and 1 respectively. Then the corresponding ratio of increase in their length will be

(a)32(b)316(c)1(d)364

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A)

Let ratio of length be a

Let ratio of radii be b

Let ratio of Young's modulus be c

We know y=F/AΔL/L

∴ΔL=FLAY

ΔLsΔB=(FSFB)(LSLB)(ABAS)(YBYS)

=(3M2M)(a)(1b2)(1c)

=3a2b2c

=3×22×42×1

=316

Hence b is the correct answer.

Answer 2

Answer:

the above answer is bohas

Explanation:

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