If the ratio of masses of So³and 0², gases confined in a vessel is 1:1, then the ratio of these partial pre
would be
1) 5:2
2) 2 : 5.1
3) 2:2
41:2
Answers
Answered by
0
Answer:
Correct option is
B
2:5
Let m be the mass of SO
3
and O
2
enclosed in the vessel.
Number of moles of SO
3
=
80
m
Number of moles of O
2
=
32
m
Partial pressure of SO
3
,P
A
=
80
m
×
V
R×T
Partial pressure of O
2
,P
B
=
32
m
×
V
R×T
Now,
P
B
P
A
=
80
m
×
m
32
=
5
2
Hence, the ratio of partial pressure of SO
3
and O
2
is 2:5.
Answered by
0
Answer:
Correct option is
B
2:5
Let m be the mass of SO
3
and O
2
enclosed in the vessel.
Number of moles of SO
3
=
80
m
Number of moles of O
2
=
32
m
Partial pressure of SO
3
,P
A
=
80
m
×
V
R×T
Partial pressure of O
2
,P
B
=
32
m
×
V
R×T
Now,
P
B
P
A
=
80
m
×
m
32
=
5
2
Hence, the ratio of partial pressure of SO
3
and O
2
is 2:5.
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