if the ratio of maximum intensity and minimum intensity of interference is 9:1.Find the ratio of intensity of sources....??????plzzz give answer correctly with explanation.
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The ratio of the intensity of sources be 4:1
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Process
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Let i1 and i2 be the intensity of sources.
Imax /Imin = {(i1)^½ +(i2)^½} ² /{(i1) ^½ - (i2)^½ }²
(9/1)^½ = {(i1)^½+(i2)^½} /{(i1)^½ - (i2) ^½}
{(4)^½ +(1)^½}/{(4)^½ - (1)^½} = {(i1)^½ +(i2)^½} / {(i1)^½ - (i2) ^½}
So, i1 = 4 and i2 = 1
So the ratio of the intensity of sources = i1 :i2 =4:1 __(ans) __
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Hope I helped u.
________________________
.
Process
_______
Let i1 and i2 be the intensity of sources.
Imax /Imin = {(i1)^½ +(i2)^½} ² /{(i1) ^½ - (i2)^½ }²
(9/1)^½ = {(i1)^½+(i2)^½} /{(i1)^½ - (i2) ^½}
{(4)^½ +(1)^½}/{(4)^½ - (1)^½} = {(i1)^½ +(i2)^½} / {(i1)^½ - (i2) ^½}
So, i1 = 4 and i2 = 1
So the ratio of the intensity of sources = i1 :i2 =4:1 __(ans) __
________________________
Hope I helped u.
________________________
rakeshmohata:
I max = square of sum of amplitude of the two sources
and I min = the square of difference of amplitude of the two sources
amplitude² = Intensity so
amplitude =(intensity) ^½
now I hope u got it
ya ....somewhat.....better.....
i1 and i2 are intensity... so their amplitude will be (i1) ^½
ya broo......now i get it....
thanks a lot bro..
welcome..
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