If the ratio of nth terms of two A.P.'s is (2n+8):(5n-3) then the ratio of the sum of their n terms is
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Given : ratio of nth terms of two AP's is (2n+8):(5n-3),
To Find : ratio of the sum of their n terms is
1). (2n+18):(5n+1)
(2). (5n-1):(2n+18)
(3). (2n+18):(5n-1)
(4). None of these.
Solution:
Sₙ = (n/2) ( first term + nth term )
aₙ = 2n + 8
=> a₁ = 2(1) + 8 = 10
Sₙ = ( n/2)(10 + 2n + 8) = n ( n + 9)
aₙ = 5n - 3
a₁ = 5(1) - 3 = 2
Sₙ = ( n/2)(2 + 5n -3) = n ( 5n -1 )/2
Ratio = n ( n + 9) / n ( 5n -1 )/2
= (2n + 18)/(5n - 1)
ratio of the sum of their n terms is (2n + 18)/(5n - 1)
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