Question

if the ratio of one side and hypotenuse of aright angled triangle is 5:3 , then how much is the other side​

Answer 1

Given: △ABC is a right angled triangle.

            Hypotenuse AC=5cm

            and AB:BC=1:2

            ⇒ AB=1x,BC=2x

In right angled △ABC, 

By pythagoras theorem

AC²=AB²+BC²

⇒5²=(1x)²+(2x)²

⇒25=x²+4x²

⇒25=5x²

⇒x=5​

Hence, AB=1x=1×\/5​=\/5​cm

             BC=2x=2×\/5​=\/25​cm

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