If the ratio of radius of base and height of a cone is 5:12 and its volume is 314 cubic metre. Find its perpendicular height and slant height ( = 3.14)
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Answered by
35
Let the radius be 5a
Height = 12a
Volume = pi r^2 h / 3
=> 314 = 3.14 × (5a)^2 × (12a) / 3
=> 100 × 3 = 25a^2 × 12a
=> 300 = 300a^3
=> a^3 = 1
=> a = 1
Radius = 5 m
Height = 12 m
Slant height = sqrt ( 12^2 + 5^2)
= sqrt ( 144 + 25)
= sqrt (169)
= 13 m
Height = 12a
Volume = pi r^2 h / 3
=> 314 = 3.14 × (5a)^2 × (12a) / 3
=> 100 × 3 = 25a^2 × 12a
=> 300 = 300a^3
=> a^3 = 1
=> a = 1
Radius = 5 m
Height = 12 m
Slant height = sqrt ( 12^2 + 5^2)
= sqrt ( 144 + 25)
= sqrt (169)
= 13 m
Answered by
12
here is your answer
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