If the ratio of specific heat capacities of a gas is 1.4 and its density at S.T.P. is 0.09 kg/m². Calculate the values of specific heat capacities at constant pressure and at constant volume. 14
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Answer:
γ−1
PV
Explanation:
At constant pressure, change in internal energyΔU=nC
v
ΔT
Now,
C
v
C
p
=γ
⇒1+
C
v
R
=γ
⇒C
v
=
γ−1
R
Using Charle's law, final temperature=2\times initial temperatue=2T
Thus, ΔU=nC
v
(2T−T)=nC
v
T=
γ−1
nRT
=
γ−1
PV
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