If the ratio of sum of n terms of two APs is (n+1):(n-1), then the ratio of
their m th terms is:
(a) (m +1): 2m
(b) (m + 1): (m - 1)
(c) (2m - 1): (m + 1)
(d) m :(m - 1)
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The ratio of the sum of n terms of two A.P's is (7n+1):(4n+27) . ... = [7(2m – 1) + 1] : [4(2m – 1) +27] [14m – 7 +1] : [8m – 4 + 27]= [14m – 6] : [8m + 23]Thus the ratio of mth terms of two AP's is [14m – 6] : [8m + 23].
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