Question

If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the youngest? ​

Answer 1

Answer:

∴ The age difference = 75 - 27 = 48 years

Step-by-step explanation:

Given:

The ratio of ages of Kissi and Esinam is 3:5

The ratio of ages of Esinam and Lariba is 3:5

The sum of the ages of Kissi, Esinam and Lariba is 147 years

To find:

The age difference between the oldest and the youngest

Solution:

We have,

Kissi                   Esinam                  Lariba

3                             5

                              3                             5

(3×3)                    (5 × 3)                      (5 × 5)

 9                            15                            25

∴ The ratio of ages of Kissi, Esinam and Lariba = 9 : 15 : 25

Let the ages be:

Kissi's age → 9x

Esinam's age → 15x

Lariba's age → 25x

Now, according to the question we can form and equation as,

9x + 15x + 25x = 147

⇒ 49x = 147

⇒ x =

⇒ x = 3

By substituting the value of x, we get

Kissi's age → 9 × 3 = 27 years

Esinam's age → 15 × 3 = 45 years

Lariba's age → 25 × 3 = 75 years

∴ The age difference = 75 - 27 = 48 years

Thus, the age difference between the oldest and the youngest is 48 years.