If the ratio of the areas of two circles is 9:1 then the ratio of their perimeter is
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Answer:
ratio of perimeter = 3 : 1
Step-by-step explanation:
area of 1st circle = πr1^2
area of 2nd circle = πr2^2
a / q , πr1^2 / πr2^2 = 9 / 1
r1^2 / r2^2 = 9 / 1
r1 / r2 = 3 : 1
now , perimeter of circle 1 = 2πr1 = 6π
perimeter of circle 2 = 2πr2 = 2 π
then , ratio of perimeter = 6π / 2π
ratio of perimeter = 3 : 1
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