If the ratio of the areas of two squares is 121:529, what is the ratio of their perimeters
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Step-by-step explanation:
let a be the side of one square and b be tbe side of other square
given a² : b² = 121 : 529
therefore a : b = 11 : 23
now perimeter is first square = 4a and perimeter of 2nd square is 4b
therefore 4a : 4b = 4(a : b) => 4(11 : 23) => 44 : 92 => 11 : 23
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