if the ratio of the areas of two squares is 9:1, find the ratio of their perimeters
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perimeter = 3 : 1
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gowtham27:
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According to question
Area1 : Area2 = 9 : 1
Let the side of squares be a and b
a^2 /b^2 = 9/1
=> (a/b) ^2 = 9/1
=> a/b = 3/1
=> 4a/4b = 3/1
Perimeter of square 1 : Perimeter of square 2
= 3:1
Hope it will help you.....
Please mark as brainliest if you liked the solution
Area1 : Area2 = 9 : 1
Let the side of squares be a and b
a^2 /b^2 = 9/1
=> (a/b) ^2 = 9/1
=> a/b = 3/1
=> 4a/4b = 3/1
Perimeter of square 1 : Perimeter of square 2
= 3:1
Hope it will help you.....
Please mark as brainliest if you liked the solution
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