Question

if the ratio of the corrosponding sides of similar triangles is 3:4 what will be the ratio of their areas​

Answer 1

Answer:

MATHS

If the ratio of the corresponding sides of two similar triangles is 3:4, then the ratio of their perimeters is:

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ANSWER

Ratio corresponding to similar triangle =

4

3

i.e.

PQ

AB

=

4

3

QR

BC

=

4

3

PR

AC

=

4

3

AB=

4

3PQ

BC=

4

3QR

AC=

4

3PR

PerimeterofPQR

PerimeterofABC

=

PQ+QR+RP

AB+BC+CA

=

PQ+QR+PR

4

3

(PQ+QR+PR)

=

4

3

solution

Answer 2

Answer:

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Step-by-step explanation:

Ratio corresponding to similar triangle = 3/4

i.e.

AB/PQ = 3/4

BC / QR = 3/4

AC/ PR = 3/4

AB= 3PQ/4

BC= 3 QR/4

AC= 3PR/4

Perimeter of ABC/ PerimeterofPQR= AB+BC+CA/

PQ + QR + RP = 3/4 (PQ+QR+PR) / PQ + QR + PR = 3/4

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