if the ratio of the digits of a two number is 2:3 then find the possible number
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let, the 2 digit number be : 10x+y
if, x:y=2:3 then, y=3x/2
now, for : 0 < x < 9 & 0 < y < 9.
the possible values are :
x=2, then , y=3,23
x=3, then , y=4.5, you cannot make a valid number so skip odd numbers
x=4, then, y=6,46
x=6, then, y=9,69
x=7, then , y=10.5 this is greater than 9 so, stop here .
So, the values obtained are : 23, 46, 69.
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