If the ratio of the efficiency of two pipes A,B and C is 5:4:6 and the time taken by pipes to fill 30% of the tank is 8 hours.Then find in how many hours will fill by pipe A alone?
Answers
Answer:
The amount of time that B takes to fill the tank, pipe A fills it in its one fourth time
Pipe C takes 3 times as much as time taken by A
Time for completing the work is 33 hours
Concept used :
Time taken by a person to complete a work is inversely proportional to his efficiency
Person's per day work = Total work/Number of days taken by him to complete the work
Calculations :
Ratio of time for A to B is 1 : 4
Ratio of time taken for A to C is 1 : 3
Ratio of time for A, B and C will be 1 : 4 : 3
So ratio of the efficiencies for A, B and C will be
A : B : C = 1 : (1/4) : (1/3)
⇒ 12 : 3 : 4
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Let the work done by A, B and C per hour be 12x, 3x and 4x units respectively
A, B and C per hour work = 12x + 3x + 4x = 19x units
Total work = 19x × 33
Total work = 627x units
Time taken by A and B to complete the work = 627x/15x
⇒ 41.8 hours
∴ Total time taken by a and B will be 41.8 hours