Question

If the ratio of the maximum height attained and the minimum velocity of two projectile is 2:1 then the ratio of their range would be
a)2✓2:1 b) ✓2:1 c) 2:1 d) 4:1 ​

Answer 1

Answer:

Explanation:

we know that,

h = u^2sin^2theta/2g

and

minimum velocity of a projectile is at maximum height

therefore at maximum height the projectile is no longer to go up or go down it just goes horizantally for few fraction of seconds thereforeit has only horizantal of component of velocity and it is,

u cos of theta

therfore,

if wetake ration of above quantities

h/u = u^2sin^2theta/ucostheta2g

= u tan theta sin theta

2ucostheta2g= u^2sin^2theta

but R= u^2sin2theta/g

therefore if wesubstitute value of R in above equation weget

ucostheta =2hsin2theta/sin^2theta