if the ratio of the shortest and the longest sides of a right triangle 3:5 and its perimeter is 36 cm, find the area of the triangle.
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we know longest side in right angeled triangle is hypotenuse
let the ratio be x
so hypotenuse = 5x
and other short side = 3x
another side considered as y
so by using Pythagoras theorum
hypotenuse ^2 = one side ^2 + another side ^2
(5x)^2 = (3x)^2 + y^2
25x^2 = 9x^2 + y^2
y^2 = 25x^2 - 9x^2
y^2 = 16x^2
y = 4x
so all sides are in ratio
3x : 4x : 5x
perimeter = 36
3x + 4x + 5x = 36
12 x = 36
x = 3
so sides are
3x = 3 × 3 = 9
4x = 4 × 3 = 12
5x = 5 × 3 = 15
area of right angeled triangle = 1/2 × 9 × 12
= 54 sq cm
let the ratio be x
so hypotenuse = 5x
and other short side = 3x
another side considered as y
so by using Pythagoras theorum
hypotenuse ^2 = one side ^2 + another side ^2
(5x)^2 = (3x)^2 + y^2
25x^2 = 9x^2 + y^2
y^2 = 25x^2 - 9x^2
y^2 = 16x^2
y = 4x
so all sides are in ratio
3x : 4x : 5x
perimeter = 36
3x + 4x + 5x = 36
12 x = 36
x = 3
so sides are
3x = 3 × 3 = 9
4x = 4 × 3 = 12
5x = 5 × 3 = 15
area of right angeled triangle = 1/2 × 9 × 12
= 54 sq cm
pravinsir:
mark it as brainliest plz
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