Question

If the ratio of the specific heats of steam is 1.33 and R=8312J/kmole k find the molar heat capacities of steam at constant pressure and constant volume

Answer 1

Answer:

Solution

γ=cp/cv=1.33

R = 8.312 J/k mole K

Cp=γR/γ−1

=1.33×8.312 /1.33−1

= 11054.96 /0.33

= 33.50 kJ/k mole K

similarly

cv = R /γ−1

=25.187 kJ/ k moke K

Answer 2

answer is cp is33.5 kj/mole-k

cv is 25.19kj/mole-k