If the ratio of the sum of first n term of two A.P is (7n +1): (4n + 27) find the ratio of their Mth term
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Let a1, a2 be the first terms and d1, d2 the common differences of the two given A.P.'s. Then, the sums of their n terms are given by
Sn=2n[2a1+(n−1)d1]
And,
Sn′=2n[2a2+(n−1)d2]
Therefore,
Sn′Sn=2n[2a2+(n−1)d2]2n[2a1+(n−1)d1]=2a2+(n−1)d22a1+(n−1)d1
⟹2a2+(n−1)d22a1+(n−1)d1=4n+277n+1 ....(1)
To find the ratio of the mth terms of the two given AP's, we replace n by (2m-1) in equation 1.
Therefore,
2a2+(2m−2)d22a1+(2m−2)d1=4(2m−1)+277(2m−1)+1
⟹a2+(m−1)d2a1+(m−1)d1=8m+2314m−6
Hence, the ratio of the mth terms of two AP's is (14m−6):(8m+23).
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