If the ratio of the sum of the frirst n terms of two A.Ps is ( 7n + 1 ) : ( 4n + 27 ) , then find the ratio of their 9th terms .
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Sn/Sn=(7n+1)/(4n+27)
n/2(2a+(n-1)d). 7n+1
___________= _____
n/2(2A+(n-1)D. 4n+27
let the n be 17.
Then,
(2a+16d)/(2A+16D)=120/95
2(a+8d)/2(A+8D)=24/19
(a+8d)/A+8D=24/19
9th term=a+8d
IT IS CLASS 10TH BOARD QUESTION.
PLZ MARK IT AS BRAINLIEST.
n/2(2a+(n-1)d). 7n+1
___________= _____
n/2(2A+(n-1)D. 4n+27
let the n be 17.
Then,
(2a+16d)/(2A+16D)=120/95
2(a+8d)/2(A+8D)=24/19
(a+8d)/A+8D=24/19
9th term=a+8d
IT IS CLASS 10TH BOARD QUESTION.
PLZ MARK IT AS BRAINLIEST.
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5
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Plz mark as Brainliest..
Plz mark as Brainliest..
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