if the ratio of the sun of n terms of two A.P is 14 - 4n : 3n + 5 find the ratio of their 8th term
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14-32/24+5=-18/29 will be the required ratio.
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Step-by-step explanation:
- 14-4n/3n-3=n/2(2a +(n-1)d) divided by n/2(2A+(n-1)D) then 14-4n/3n-3=(2a+(n-1)d)/(2A +(n-1)D) . On dividing by 2 to both the side we will get a+(n-1/2)d/2A+(n-1/2)D=7-7n/3n-3/2 . For getting 8th term put n-1/2=7 and then find the value of N which will be n=15 . As we know a8=Sn9-Sn8
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