If the ratio of the volume of two spheres
is 1 : 8, then the ratio of their surface
area is
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Answer:
Let the volume of the smaller sphere be 4/3πr^3
And that of bigger sphere be 4/3πR^3
Now,
Vol of small sphere/Vol of bigger sphere= 4/3πr^3÷4/3πR^3=1÷8
This gives,
r^3/R^3 =1/8
r/R=1/2
so,
r=1
and R=2
Now the ratio of their surface areas is:-
SA of smaller sphere/SA of bigger sphere=
4π1^2/4π2^2
=1/4
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