Question

if the ratio of the volumes of two solid spheres is 1:8 , the ratio their curved surface area is​

Answer 1

Step-by-step explanation:

volume of a sphere of radius 'r'=4/3πr^3

let r1 be the radius of the first sphere

and r2 and be the radius of the second sphere

Given,ratio of their volumes is: v1:

V2=1:8

4/3πr1^3:4/3πr3^2h=1:8

r1^3 =r2^3 =1:8

r1:r2 =1:2

surface area of a sphere of radius'r' =4πr^2

Now, ratios of their surface areas is:

s1:s2

= 4πr1^2:4πr1^2h

= r1^2:r2^2

= 1^2:2^2

= 1:4

hopes, it help you