Question

if the ratio of two number is 3:5 and their sum is 40 then the smaller of the two number is___​

Answer 1

Answer:

➡️Smallest of the two number is 15

Step-by-step explanation:

⏺️Let the ratio be 3x and 5x

A/q

Sum of the ratio is 40

So,

➡️3x + 5x = 40

➡️8x = 40

➡️x = 40 / 8

➡️x = 5

So,

3x = 3 x 5 = 15

5x = 5 x 5 = 25

So, the result came = 15(smaller number than 25)

⏺️ Hey mate hope it will be helpful to you

Answer 2

$\Large{\underline{\underline{\mathfrak{\tt{\red{Solution}}}}}}$

$\Large{\underline{\mathfrak{\tt{\orange{Given}}}}}$

• the ratio of two number is 3:5
• sum of these two number is 40.

$\Large{\underline{\mathfrak{\tt{\orange{Find}}}}}$

• Smallest number .

$\Large{\underline{\underline{\mathfrak{\tt{\orange{Explanation}}}}}}$

Let,

• first number = x
• Second number = y

A/C to question

(the ratio of two number is 3:5 )

$:\mapsto\tt{\:x:y\:=\:3:5} \\ \\ :\mapsto\tt{\:\dfrac{x}{y}\:=\:\dfrac{3}{5}} \\ \\ :\mapsto\tt{\:5x-3y\:=\:0..........equ(1)}$

Again,

( sum of these two number is 40. )

$:\mapsto\tt{\:x+y\:=\:40......equ(2)}$

multiply by 5 in equ(2) ,

$:\mapsto\tt{\:5x+5y\:=\:200.........equ(3)}$

Subtract equ(1) &equ(2)

$:\mapsto\tt{\:(-3y-5y)\:=\:-200} \\ \\ :\mapsto\tt{\:-8y\:=\:-200} \\ \\ :\mapsto\tt{\:y\:=\:\cancel{\dfrac{-200}{-8}}} \\ \\ :\mapsto\tt{\green{\:y\:=\:25}}$

keep value of y in equ(1),

$:\mapsto\tt{\:5x-3\times25\:=\:0} \\ \\ :\mapsto\tt{\:5x\:=\:75} \\ \\ :\mapsto\tt{\:x\:=\:\cancel{\dfrac{75}{5}}} \\ \\ :\mapsto\tt{\green{\:x\:=\:15}}$

$\Large{\underline{\underline{\mathfrak{\tt{\orange{Hence}}}}}}$

$:\mapsto\tt{\blue{\:Value\:of\:first\:number\:(x)\:=\:15}} \\ \\ :\mapsto\tt{\blue{\:Value\:of\:Second\:number\:(y)\:=\:25}}$

$\Large{\underline{\underline{\mathfrak{\tt{\orange{Since}}}}}}$

$:\mapsto\tt{\red{\:Smallest\:number\:will\:be\:(x)\:=\:15}}$

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