if the ratio of two roots of the quadratic equation ax2+bx+c=0[a not equal to 0] is 1:r, then show that r+12 r = 0 b2 ac
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ax2+bx+c=0
roots are 2a−b+b2−4ac
α=2a−b+b24ac β=2a−b−b2−4ax
r=βα=(−b+b2−4ac−b+b24ac)
=−(b+b2−4ac)b−b2−4ac×b−b2−4acb−b2−4ac
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