if the reading of voltameter is 18 V and two resistors of 50ohm and 24 ohm are connected in series and EMF is 30 V find the resistance of voltameter
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The voltage across the 24 ohms resistor is 30−18=12 v
The current flowing is 12v/24Ω=0.5 A
The current through the 50 Ω resistor is 18v/50Ω=0.36 A
So the current through the voltmeter is 0.5A−0.36A=0.14 A
The resistance of the voltmeter is 18v/0.14A=128.6Ω
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