if the reflective index of water for light going for light from air to water be 1.33 what will be the refractive index for going from water
Answers
Answered by
0
speed of light in water
v
=
225
,
407
,
863.2
meter/second
Explanation:
Formula for refractive index
n
=
c
v
where
n=
refractive index
c
=
299792458
speed of light in a vacuum in
meter per second
v
=
phase velocity of light in the medium
Solve for
v
v
=
c
n
v
=
299792458
1.33
v
=
225
,
407
,
863.2m/sec
I hope the explanation is useful.
v
=
225
,
407
,
863.2
meter/second
Explanation:
Formula for refractive index
n
=
c
v
where
n=
refractive index
c
=
299792458
speed of light in a vacuum in
meter per second
v
=
phase velocity of light in the medium
Solve for
v
v
=
c
n
v
=
299792458
1.33
v
=
225
,
407
,
863.2m/sec
I hope the explanation is useful.
Answered by
0
Answer:
2.25 × 10⁸ m / sec
Explanation:
Given :
Refractive index of water = 1.33
Speed of light in air = 3 × 10⁸ m / sec.
We know :
Refractive index = Speed of light in air / Speed of light in water
Speed of light in water = Speed of light in air / Refractive index.
Putting value we get :
Speed of light in water = 3 × 10⁸ m / sec / 1.33 .
Speed of light in water = 2.25 × 10⁸ m / sec
Hence speed of light in water is 2.25 × 10⁸ m / sec
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