Question

if the refractive index of benzene is 1.50. then find velocity of light benzene

Answer 1

n=c/v

c=3×10^8

1.50=3×10^8/v

v=3×10^8/1.5

v=2×10^8m/s

Answer 2

Answer:

v = 2 × 10⁸ m / sec

Explanation:

Given :

Refractive index of benzene = 1.50

We know :

Speed of light = 3 × 10⁸ m / sec

We know formula for n :

n = speed of light in vacuum / speed of light in benzene

n = c / v

1.5 = 3 × 10⁸ / v

v = 2 × 10⁸ m / sec