if the refractive index of denser medium is 1.5 then what is the value of critical angle?
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Given,
Refractive Index of Denser Medium = 1.5 or, 3/2
sin C = 1/μ
.... 'C' is the Critical Angle,
sin C = 1/(3/2)
sin C = 2/3
sin C = sin 42°
C = 42°
I hope this helps.
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