Physics, asked by meanonymous337, 8 hours ago

If the refractive index of lemon-sugar water is 1.38, then the speed of light in it would approximately be: 2.17 x 108 m/s 2.33 108 m/s O 2.45 x 108 m/s 4.14 x 108 m/s​

Answers

Answered by Johnsonmijo
0

Answer:

The speed of light in lemon-sugar water will be 2.17 × 10⁸ m/s

Explanation:

The refractive index of a material is the ratio of the speed of light in a vacuum to the speed of light in that material. ie;

   n = c/v

⇒ v = c/n

n is the refractive index, c is the velocity of light in vacuum and v is the velocity of light in the material whose refractive index is to be found.

The refractive index of lemon-sugar water, n = 1.38

The speed of light in vacuum, c = 3 × 10⁸ m/s

∴ Speed of light in lemon sugar water, v = (3 × 10⁸) / (1.38)

                                                                v = 2.17 × 10⁸ m/s

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