Question

If the refrective index of rarer medium with respect to a denser medium is 0.5,what is the critical angle?

Answer 1

Answer:

critical angle is 90 degres

and when it passes through the rarer medim to denser medim it bends towards the normal

Answer 2

The critical angle = 30°

Explanation:

We know according to snell's law μ = sini / sinr

here μ is the refractive index of medium

In case of total internal reflection sin r = 1

Thus μ = sin i

In the question μ = 0.5

Therefore sin i = 0.5 or  critical angle of incidence = 30°