If the reistance of the bulb in 100Ω and potential difference is 240v. then find the electric power.
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Explanation:
According to Ohm’s Law
R=V/I Where,R=Resistance , V=Voltage ,I=Current..
100w at 220v, I=P/V.
=100/220=0.454Amp.
R=V/I; 220/0.454=484.56 ohms.
When it is connected to 240 Volts
I=V/R; 240/484.56=0.495 ~ 0.50 Amps.
Power consumed(P)=V×I; 240×0.50=120 W.
The bulb will consume 120 W at 240 Volts. 20W difference.
This is not a loss the bulb glows brighter than it used in 220 volts.
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