Question

if the relation between x and y is 5y-3x=10 and the mean deviation mean for x is 12 then the mean deviation of y about mean is​

Answer 1

5y-3x=10

x=12

5y-3×12=10

5y-36=10

5y=46

y=46/5

y=9.2

Answer 2

Answer:

y=a+bx

y=3/5x+10/5

=|b|*12

=3/5* 12

=36/5

=7.20