Math, asked by kellyraianya, 1 day ago

If the relationship in the table is linear, explain how to find the initial value

Answers

Answered by urkudkarujwala
0

Answer:

35.5

Step-by-step explanation:

Because there is no table to be able to see what are first values of "x" and "y" in the table, then the initial value of a linear function is the value of y of f(x), when the value of x is 0.

First we have to write a linear equation for the line which contain given points.

m = \frac{50.75-42.25}{5-3}

5−3

50.75−42.25

= \frac{4.5}{2}

2

4.5

= \frac{9}{4}

4

9

(y_{2}y

2

- y_{1}y

1

) = m (x_{2}x

2

- x_{1}x

1

)

y - 42.25 = \frac{9}{4}

4

9

(x - 3)

y = \frac{9}{4}

4

9

x - \frac{27}{4}

4

27

+ 42.27

y = \frac{9}{4}

4

9

x + 35.5

If x = 0 , y = 35.5

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