If the relationship in the table is linear, explain how to find the initial value
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Answer:
35.5
Step-by-step explanation:
Because there is no table to be able to see what are first values of "x" and "y" in the table, then the initial value of a linear function is the value of y of f(x), when the value of x is 0.
First we have to write a linear equation for the line which contain given points.
m = \frac{50.75-42.25}{5-3}
5−3
50.75−42.25
= \frac{4.5}{2}
2
4.5
= \frac{9}{4}
4
9
(y_{2}y
2
- y_{1}y
1
) = m (x_{2}x
2
- x_{1}x
1
)
y - 42.25 = \frac{9}{4}
4
9
(x - 3)
y = \frac{9}{4}
4
9
x - \frac{27}{4}
4
27
+ 42.27
y = \frac{9}{4}
4
9
x + 35.5
If x = 0 , y = 35.5
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