if the rellocity of body is
increased 4% then what
is the approximate % change
in its kE
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Answer:
The Kinetic Energy (KE) of a body is given by KE=0.5mv^2.
Where m is the mass of the body and v is the velocity of the body.
Now new velocity u= v + (4/100)v = 1.04v
Therefore new kinetic energy E=(1/2)m(1.04v)^2 = 1.08KE (Approx.)
Change in KE = (1.08)KE - KE = 0.08KE.
Therefore Percentage increase in KE = ( (Change in KE)/(Original KE))x100%
which becomes 8%.
Thus a increasing the velocity by 4% increases the KE by approximately 8%.
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