Question

If the remainder of (5k+2)(5k+3)(5k+4)/5 is a natural number then find it
grade 10 maths
real numbers

Answer 1

Answer:

Let me tell you a simple formulae that belongs to basic maths

Step-by-step explanation:

Remainder((a*b*c)/d) = Remainder((remainder(a/d)*remainder(b/d)*remainder(c/d))/d)

It may look complicated. But just analyse it. So remainder of (5k+2)(5k+3)(5k+4)/5 will be same as remainder of (5k+2)/5 which is 2 + remainder of (5k+3)/5 which is 3 + remainder of (5k+4)/5 which is 4 whole divided by 5.

Which is remainder of 9/5 which is 4.

Therefore the answer is 4.

Answer 2

Answer:

Remainder((a*b*c)/d) = Remainder((remainder(a/d)*remainder(b/d)*remainder(c/d))/d)

It may look complicated. But just analyse it. So remainder of (5k+2)(5k+3)(5k+4)/5 will be same as remainder of (5k+2)/5 which is 2 + remainder of (5k+3)/5 which is 3 + remainder of (5k+4)/5 which is 4 whole divided by 5.

Which is remainder of 9/5 which is 4.

Therefore the answer is 4.