Question

if the remainder when two polynomial ax^3+3x^2-13 and 2x^3-5x+a are divided by x+2 is same find the value of a​

Answer 1

Answer:

f(x)=ax^3+3x^2-13

f(-2)=a(-2)^3+3(-2)^2-13

     =a(-8)+3(4)-13

     = -8a+12-13

     = -8a-1

f(x)=2x^3-5x+a

f(-2)=2(-2)^3-5(-2)+a

     =2(-8)+10+a

     = -16+10+a

     = -6+a

now, the remainder is the same

so, -8a-1=-6+a

     -1+6=a+8a

         5=9a

         a=5/9

Step-by-step explanation: