Question

If the remainder, when x3^-ax2^+11x-6 is divided by x-4 is 6, then the value of 'a' is:

Answer 1

Step-by-step explanation:

The remainder when f(x) is divided by x-a is f(a)

Here f(x)=x³-ax²+11x-6 and a=4 remainder=6

6=(4)³-a(4²)+11(4)-6

6=216-16a+44-6

6=254-16a

16a=254-6

16a=248

a=248/16=15.5