Question

If the remainder, when x3^-ax2^+11x-6 is divided by x-4 is 6, then the value of 'a' is:

Answer 1

Answer:

-60

Step-by-step explanation:

Given f(x)=x^3 −6x^2+11x−6

Divisor is (x+2)

⇒a=−2

Therefore, according to remainder theorem

R=f(a)

=f(−2)

=(−2)^3 −6(−2)^2 +11(−2)−6

=−60