If the reminder on division of x cube + 2 X square + kx + 3 by x minus 3 is 21 then find the value of k
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Hi friend
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Your answer
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Now,
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x - 3 = 0
=> x = 3
Then,
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p(x) = x³ + 2x² + kx + 3
=> p(3) = (3)³ + 2 × (3)² + k × 3 + 3 = 21
=> 27 + 18 + 3k + 3 = 21
=> 48 + 3k = 21
=> 3k = 21 - 48
=> 3k = - 27
=> k = - 27/3
=> k = - 9
HOPE IT HELPS
-------------
Your answer
--------------------
Now,
----------
x - 3 = 0
=> x = 3
Then,
-----------
p(x) = x³ + 2x² + kx + 3
=> p(3) = (3)³ + 2 × (3)² + k × 3 + 3 = 21
=> 27 + 18 + 3k + 3 = 21
=> 48 + 3k = 21
=> 3k = 21 - 48
=> 3k = - 27
=> k = - 27/3
=> k = - 9
HOPE IT HELPS
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