If the repetition of digits is not allowed in any
number. How many numbers of 3 digits can be
formed with the digits 0, 1, 2, 3, 4 ?
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Hey Buddy
Here's The Answer
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=> At hundreds place :- We have 4 possibilities ( 1, 2, 3, 4 ), we haven't counted 0 in it as 0 will have no value at hundreds place and the number will become a 2 digit number.
Suppose we used 1 at hundreds place.
=> At tens place :-We have 4 possibilities ( 0, 2, 3, 4 ), we haven't included 1 as we have used it before, so no number will be repeated.
suppose we used 2 at tens place.
=> At once place :- We have 3 possibilities ( 0, 3, 4 )
Now total number can be formed
=> 4 × 4 × 3
=> 48 numbers.
Hope It Helps.
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