Question

if the replacement set = [-6,-3,0,3,6,9] find the truth set of the following 2x-1>9 and 3x+7 < 1


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Answer 1

Answer:

The truth set of the following 2x-1>9 and 3x+7 < 1 is (6,9) and (-3,-6) respectively.

Step-by-step explanation:

i) 2x-1>9

For,x=6

2x-1>9

=2(6)-1>9

=12-1>9

=11>9

For,x=9

2x-1>9

=2(9)-1>9

=18-1>9

=17>9

x=(6,9)

ii) 3x+7 < 1

For,x=-3

3x+7 < 1

=3(-3)+7 < 1

=-9+7 < 1

=-2 < 1

For,x=-6

3x+7 < 1

=3(-6)+7 < 1

=-18+7 < 1

=-11 < 1

x=(-3,-6)

Answer 2

{6,9}

Given, 2x−1>9

$\bold{⟹2x>9+1⟹x> \frac{10}{2} }$

⟹x>5

From the options, option A has the set with values >5 which ∈ replacement set {−6,−3,0,3,6,9}