If the resistance of a certain copper wire is 1 ohm then the resistance of similar nichrome wire will be about?
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The equation of resistance,
R=ρ(l/a)
where,
R = resistance,
ρ = resistivity,
l = length
a =cross-sectional area.
suppose for Copper wire, R and ρ=(1.68E-8 (ohm m)) be resistance and resistivity
Similarly, for Nichrome wire let R’ and ρ’ =(130E-8 (ohm m)) be resistance and resistivity.
because the two wires are identical their length to cross sectional area is same. From given data for Copper wire, R=1 ohm. Then,
l/a=R/ρ = 1/(1.68E-8) / meter.
Using the above result for the Nichrome wire, we have,
R’=(130E-8)* (1/(1.68E-8) ) (ohm)
=77.381 ohms.
Therefore, the required resistance of Nichrome wire is 77.381 ohms.
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Answer:
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Explanation:
the write answer is
60 ohms
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