If the resistance of a conductor is reduced to half its initial value, then the heating effect in the conductor will become ?
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Answered by
26
There are lot of formula to find heat produced in the conductor.
P = I²R , P = VI , P = V²/R
which one should be used ? confusion ?
Don't be confuse dud , just use P = V²/R.
because here question didn't say about altering of voltage. means, voltage remains same. hence, we should Power = V²/R.
now tell me , when resistance of a conductor is reduced to half , then power should be ?
of course , double
because power is inversely proportional to resistance , if resistance is reduced to haft then power will be double.
hence, the power is doubled
P = I²R , P = VI , P = V²/R
which one should be used ? confusion ?
Don't be confuse dud , just use P = V²/R.
because here question didn't say about altering of voltage. means, voltage remains same. hence, we should Power = V²/R.
now tell me , when resistance of a conductor is reduced to half , then power should be ?
of course , double
because power is inversely proportional to resistance , if resistance is reduced to haft then power will be double.
hence, the power is doubled
Answered by
25
Here is the answer: If the resistance of a conductor is reduced to half its initial value, then the heating effect in the conductor will become half.
When current transmit through a conductor, heat energy is generated in the conductor.
The heating effect of an electric current depends on various factors: The resistance, R of the conductor.
A greater the resistance produces more heat.
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