if the resistance of conducting wire p is four times resiatance of conducting wire Q then the ratio of cross sectional areas of wires are
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wireP =4(wireQ) the resistance ATC
r(P)=ρl/a
r(Q)=4(ρL/A)
thus, r(P/Q)=1/4(l/a/L/A)
this is the ratio . i might be wrong.
Answered by
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The relation between resistance and cross-sectional wire is given below:
R= p L/A, where R- Resistance, L= length , A- cross-sectional area of the wire, p- constant
As given: Resistance of P= 4×( Resistance of Q)
For wire P:
R(P) = p L(P)/A(P)---------(1)
For wire Q:
R(Q) = p L(Q)/A(Q)--------(2)
Also given: R(P)= 4R(Q)-----(3)
Dividing (1) by (2), and using the relation(3):
[ L(P) × A(Q) ] / [ A(P) × L(Q) ] = 4
or, A(P) : A(Q) = L(P) : 4 L(Q)--------( Ans )
Therefore we can say that the ratio of cross-sectional areas of the two wires P and Q is equal to the ratio of their lengths in 1:4 ratio.
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