If the resistance of conducting wire p is four times the resistance of conducting wire Q then the. Area of cross sectional of area of the wire is
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According to the question the resistance of conducting wire p is four times the resistance of conducting wire Q. So, first of all let the resistance of the wire p is m1 and the resistance of the wire q is m2
Now according to the expression of resistance
R= k /v [where v= AREA]
Now, for wire p,
m1= k/v1
Now, for wire q,
m2= k/v2
m1/m2= v1/v2
4m2/m2= v1/v2
v1/v2= 1/4
Hence the answer is 1/4
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