Question

If the resistance of conducting wire p is four times the resistance of conducting wire Q then the. Area of cross sectional of area of the wire is​

Answer 1

Answer -

Ap : Aq = 1 : 4

● Explaination -

# Given -

Rp = 4Rq

# Solution -

You didn't say anything about length of wires so I'll assume both wires are made of same material and have same length.

Resistance of wire P,

Rp = ρl / Ap

Resistance of wire Q,

Rq = ρl / Aq

Taking ratio,

Rp/Rq = (ρl/Ap) / (ρl/Aq)

4 = Aq / Ap

Aq / Aq = 1/4

Therefore, ratio of cross sectional areas is 1:4.

Hope this helps...

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